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-5x^2-13x+42=6x^2
We move all terms to the left:
-5x^2-13x+42-(6x^2)=0
determiningTheFunctionDomain -5x^2-6x^2-13x+42=0
We add all the numbers together, and all the variables
-11x^2-13x+42=0
a = -11; b = -13; c = +42;
Δ = b2-4ac
Δ = -132-4·(-11)·42
Δ = 2017
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{2017}}{2*-11}=\frac{13-\sqrt{2017}}{-22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{2017}}{2*-11}=\frac{13+\sqrt{2017}}{-22} $
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